.

Tuesday, January 7, 2014

Hess Law Lab

Objective To determine of arouse ups from three exothermic fightions and wonder the Hess Law Summary Based on this audition, we have break down three related exothermic receptions involving atomic number 11 hydroxide. The first reception (Part A), steadfast atomic number 11 hydroxide give break into body of water. The heat nominate by this reaction (?H1) and this called as the heat of answer of material NaOH. From the test we have managed to intractable that ?H1 = -41.84 KJ/mol In the twinkling reaction (Part B), an aqueous solution of NaOH is allowed to react with an aqueous solution of HCl. This is a neutralization reaction in the midst of a strong acid and strong base. Therefore the heat of reaction (?H2) is called as the heat of neutralization of HCl and NaOH solutions. The ?H2 calculated from this experiment is -6.6944KJ/mol. This is because the heat content changes when 1 groyne of H+ ions from an acid (HCl) reacts with one mole of OH- from an alkali (NaOH) to form one mole of water molecules down the stairs the stated conditions of the experiment. In the final reaction of the experiment (Part C), potent NaOH willing react with an aqueous solution of HCl. This reaction is in any case the combination of the first and two reactions. The solid NaOH will dissociate into its ions as it dissolves in the acid solution which is thence neutralize by the acid solution.
Ordercustompaper.com is a professional essay writing service at which you can buy essays on any topics and disciplines! All custom essays are written by professional writers!
Thus the heat of the reaction (?H3) is tell be equal to (?H1+?H2). It is called the heat of solution of solid NaOH. From our computer science it known that ?H3 is -58.6 kJ/mol. When ionic solid dissolves in water! , heat was librated. reaction 1: Dissolving solid atomic number 11 hydroxide in water. NaOH(s) ---> Na+(aq) + OH-(aq) + heat Reaction 2: Reaction of sodium hydroxide solution with dilute hydrochloric acid. Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) ---> Na+(aq) + Cl-(aq) + H2O Reaction 3: Reaction of solid sodium hydroxide with dilute hydrochloric acid solution....If you want to get a blanket(a) essay, order it on our website: OrderCustomPaper.com

If you want to get a full essay, visit our page: write my paper

No comments:

Post a Comment